In the below given synthetic sequence,the product "$C$" is

In the following reaction,the product $(A)$ is:

The major product ($70\%$ to $80\%$) of the reaction between $m$-dinitrobenzene with $NH_4HS$ is

$2-$Aminocyclohexane$-1-$ol on treatment with $HNO_2$ produces

$RCONH_2$ is converted into $RNH_2$ by means of Hofmann bromamide degradation. In this reaction,$RCONHBr$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
$1.$ How can the conversion of $(i)$ to $(ii)$ be brought about?
$(A)$ $KBr$
$(B)$ $KBr + CH_3ONa$
$(C)$ $KBr + KOH$
$(D)$ $Br_2 + KOH$
$2.$ Which is the rate determining step in Hofmann bromamide degradation?
$(A)$ Formation of $(i)$
$(B)$ Formation of $(ii)$
$(C)$ Formation of $(iii)$
$(D)$ Formation of $(iv)$
$3.$ What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?
Give the answer for question $1$,$2$,and $3$.

The coloured major product formed in the above reaction is: